two equal sums were lent out at 9% and 4% simple interest respectively the interest earned on the Two loans add up to Rupees 1100 for 3 years find the total sum lent out
(ans will come ₹5641)
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Let the sum be Rs. x.
Therefore, Rs. x are lent at 8% for t years and Rs. x are lent at 7% for (t+
2
1
) years.
∴
100
x×t×8
+x=2560
⇒8tx+100x=256000 .....(i)
and
2×100
x×(2t+1)×7
+x=2560
⇒
200
14tx+7x+200x
=2560
⇒14tx+207x=512000 .....(ii)
Performing (i) ×7− (ii) ×4, we get
(56tx+700x)−(56tx+828x)=256000×7−512000×4
⇒700x−828x=1792000−2048000
⇒120x=256000
⇒x=2000
Putting the value of x in (i), we get
8×t×2000+100×2000=256000
⇒16000t=256000−200000
⇒16000t=56000
⇒t=
16000
56000
=3.5 years
Step-by-step explanation:
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