Two equal vector have a resultant is √3 times to either vector. The angle between them - *
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Two equal vector have a resultant is √3 times to either vector.
We have to find angle between them.
By triangle law or parallelogram law of vector addition, the magnitude of resultant R at two vectors P and Q inclined to each other at angle θ, is given by
- R² = P² + Q² + 2PQ cosθ
ATQ both vectors are of equal magnitude.
- P = Q = x
Resultant of both vectors is √3 times of either vector.
- R = √3x
By substituting the values, we get
➝ R² = P² + Q² + 2PQ cosθ
➝ (√3x)² = x² + x² + 2(x)(x) cosθ
➝ 3x² = 2x² + 2x² cosθ
➝ x² = 2x² cosθ
➝ cosθ = 1/2
➝ θ = 60° or π/3 rad
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