Two equal velocities have a resultant equal to 1×(1/2) times the value of either velocity. What is the angle between them?
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Resultant velocity is given as :
R = root v1^2 + v2^2 + 2v1v2 cos theta
Given, R = 3/2v
(3/2v)^2 = v1 + v2 + 2 v1 v2 cos theta
9/4 = (2 + 2 cos theta)
1+cos theta = 9/8
cos theta = 1/8
theta = 82.819
= ~ 82.82
Hope this helps!
R = root v1^2 + v2^2 + 2v1v2 cos theta
Given, R = 3/2v
(3/2v)^2 = v1 + v2 + 2 v1 v2 cos theta
9/4 = (2 + 2 cos theta)
1+cos theta = 9/8
cos theta = 1/8
theta = 82.819
= ~ 82.82
Hope this helps!
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