Question

Two Equal weight, suspended from the points of a uniform rod, keep it balanced If one of them is plae at 0.15 m mark, where should the other weight be suspended? Ans(0.85m) please explain​

Answer 1

Answer:

since both masses are equal and rod is balanced therefore m(.50-.15) = m x

or x = .35 m

therefore distance from balance point = .50 + .35 = .85 m