Question

Two equally charged particles are held 3.2 × 10^-3 m apart and then released from
rest. The initial acceleration of the first particle is observed to be 7.0 m/(s^2) and that of
the second to be 9.0 m/(s^2) . If the mass of the first particle is 6.3 × 10^-7 kg, what
are (a) the mass of the second particle and (b) the magnitude of the charge of each
particle?

Answer 1

Answer:

for second mass using Newton third law

F=ma for m2

m1×a1 = m2×a2

m2 = 6.3×10^-7×7.0 / 9.0

m2 = 4.9×10^-7 kg

for magnitude of charge

Fm = Fe

m1×a1 = kq^2 / r^2

q =√m1×a1×r^2 / k

q = √6.3×10^-7 × 7.0 × (3.2×10^-3)^2 / 9×10^9

q = 7.08 C