Question

Two equar electric currents are flowing perpendicular to each otici au un
AB and CD are perpendicular to each other and symmetrically placed with respect to the currents.
Where do we expect the resultant magnetic field to be zero?
(1) On AB
(2) On CD (3) On both AB and CD
(4) On both OD and OB
​

Answer 1

Answer:

Only of CO magnetic field willbe zero

Explanation:

As per right hand thumb rule

Answer 2

$\huge\star{\green{\underline{\tt{Answer :-}}}}$

(2) On CD

$\huge\star{\green{\underline{\tt{Explanation :-}}}}$

We will solve this tricky question with the help of Right Hand Thumb rule.

$\huge\star {\tt {Right\:Hand\:Thumb\:Rule :-}}$

The Right Hand Thumb Rule states that when a straight current carrying conductor is holded in the right hand such that the thumb points out in the direction of the current, then the curly fingers point in the direction of the magnetic field.

$\rule{200}2$

${\huge\tt{GIVEN}}\begin{cases}\sf{Equal\:currents\:are\:flowing\:perpendicularly}\\\sf{AB\:and\:CD\:are\:placed\:perpendicularly}\\ \sf{They\:bith\:are\:also\:placed\:symmetrically} \end{cases}$

$\huge {\tt {TO\:FIND:-}}$

The resultant magnetic field will be zero :- Where?

OBSERVE THE FIGURE 1 GIVEN AND USE RIGHT HAND THUMB RULE WITH BOTH THE CURRENTS :-

In $\tt {I_1}$, Applying right thumb rule, AB and CD at the right side of the current will experience the inward magnetic field whereas CD and AB at the left side will experience the outward magnetic field.

The figure 2 shows it perfectly.

In $\tt {I_2}$, Applying right thumb rule, AB and CD above the current will experience inward magnetic field whereas AB and CD below the current will experience outward magnetic field.

The figure 3 shows it perfectly.

The figure 4 is the final figure.

Here, In AB the magnetic field will get added.

Whereas, In CD the magnetic field will get subtracted because of the contrasting magnetic fields, resulting in zero magnetic field.

$\huge {\boxed{\tt {Hence,\:ANSWER :- (2) CD}}}$

$\rule{200}2$