two equations x-4y=0 and 4x+3y =19 have a solution (a,b) find the value of ab/ a+4b
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Answer:
A.Q.T.
x - 4y = 0
x = 4y
4x + 3y = 19
16y + 3y = 19
19y = 19
y = 1
& x = 4y = 4×1= 4
so (a,b) = (4,1)
now ab/a + 4b = 1×4/4+4×1 = 4/8 = 1/2
hope it helps you
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