two events And B have probability 0.25 and 0.50.the probability that both occur simultaneously is 0.14.then , probability that neither A nor B occur is
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Answered by
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I think 0.39 is your answer
komal8719:
yes absolutely correct but please explain
Assume P(A) = 0.25, P(B) = 0.50 and P(AB) = 0.14. You want the Probability of none of the events happening, i.e., 1 - P(AUB) = 1 - (P(A) +P(B) - P(AB)) = 1 - (0.25 + 0.50 - 0.14) = 1- (0.61) = 0.39. This is the required answer.
ohhhh thankyou soo much
wc
hi
Answered by
7
The probability that neither A nor B occur is 0.39.
Explanation:
Given : Two events A and B have probabilities
P(A) = 0.25 and P(B)=0.50
P(A and B) = 0.14
To find : P(neither A nor B )
We know that P(neither A nor B ) = 1- P(A or B)
=1- [P(A) +P(B) - P(A and B)] [∵ P(A or B) =P(A) +P(B) - P(A and B) ]
= 1- [0.25+0.50-0.14]
= 1-0.61=0.39
Hence, the probability that neither A nor B occur is 0.39.
# Learn more :
The probability of an event A occurring is 0.5 and B occurring is 0.3. If
A and B are mutually exclusive events, then find the probability of
neither A nor B occurring
https://brainly.in/question/10324665
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