Math, asked by komal8719, 11 months ago

two events And B have probability 0.25 and 0.50.the probability that both occur simultaneously is 0.14.then , probability that neither A nor B occur is​

Answers

Answered by smile4045
9

I think 0.39 is your answer


komal8719: yes absolutely correct but please explain
smile4045: Assume P(A) = 0.25, P(B) = 0.50 and P(AB) = 0.14. You want the Probability of none of the events happening, i.e., 1 - P(AUB) = 1 - (P(A) +P(B) - P(AB)) = 1 - (0.25 + 0.50 - 0.14) = 1- (0.61) = 0.39. This is the required answer.
komal8719: ohhhh thankyou soo much
smile4045: wc
smile4045: hi
Answered by JeanaShupp
7

The probability that neither A nor B occur is​ 0.39.

Explanation:

Given : Two events A and B have probabilities

P(A) = 0.25 and P(B)=0.50

P(A and B) = 0.14

To find : P(neither A nor B )

We know that P(neither A nor B )  = 1- P(A or B)

=1- [P(A) +P(B) - P(A and B)]    [∵ P(A or B) =P(A) +P(B) - P(A and B) ]

= 1- [0.25+0.50-0.14]

= 1-0.61=0.39

Hence, the probability that neither A nor B occur is​ 0.39.

# Learn more :

The probability of an event A occurring is 0.5 and B occurring is 0.3. If

A and B are mutually exclusive events, then find the probability of

neither A nor B occurring

https://brainly.in/question/10324665

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