Question

Two exactly similar wire of steel and copper are stretched by equal forces. If difference in elongation is 0.5 cm then what is elongation of each wire if Y of steel is 2×10^11 and Y of copper is 1.2×10^11

Answer 1

Answer:

Explanation:

Given :

Ys=Y for steel 20×10¹⁰ N/M²

Yc=Y for copper is 12×10¹⁰ N/M²

ΔLs+ΔLc=1 ----------------equation 1

Ys= FL/ A ΔLs

Yc=FL/ A ΔLC

⇒Ys/Yc=[FL/ A ΔLs] /[FL/ A ΔLC]

⇒Ys/Yc=ΔLc/ΔLs

⇒ΔLc/ΔLs=Ys/Yc =20x10¹⁰/12x10¹⁰ = 5/3

As ΔLs+ΔLc=1

ΔLs[1+ΔLc/ΔLs]=1

⇒ΔLs[1+5/3]=1

⇒ΔLs[8/3]=1

⇒ΔLs=3/8=0.375cm

on substituting the value of ΔLs in equation (1), we get value of ΔLc

ΔLc=0.625cm...........

Answer 2

See the attachement..

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