Chemistry, asked by ak3038269, 4 months ago

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Answers

Answered by 2020ano120644
1

Answer:

When potassium iodide solution reacts with lead(II) nitrate solution, a yellow precipitate of lead(II) iodide is formed.

Explanation:

Cu^ +2 +H ^2 S→CuS+2H^ +

The CuS formed is a black precipitate

Hg ^+2 +H ^2 S→HgS+2H ^+


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2020ano120644: Tq
ak3038269: wlcm
Answered by Anonymous
0

Answer:

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ak3038269: good evening
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