Question

two faces of 4n acts on a body at an angle of 60°find magnitude and direction of resultant force
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Answer 1

Answer:

hi good morning friend

Answer 2

Answer:

SEE BELOW

Explanation:

so, let the two forces be P and Q, Where they are VECTOR Quantities, and their magnitude is equal to 4N.

let the resultant be R vector

now, we know that R = $\sqrt{P^{2}+Q^{2}+2PQcos\theta}$

by putting the value we get $\sqrt{48}$ = 6.93N

now, for direction,

θ = tan⁻¹$\frac{Qsin\theta}{P+Qcos\theta}$

= tan⁻¹ 1/$\sqrt{3}$

= 30° , that is, between the two forces

HOPE IT HELPS YOU

:-)