Physics, asked by amanrastogi5497, 1 year ago

Two factors on which vapour pressure of lisquid depends

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Answered by Raghuroxx
3

Answer:

Answer:Vapour pressure of liquid depends upon the following factors:-

(i) Temperature: As the temperature of the liquid is raised, more molecules get evaporated and thus exert more pressure. So vapour pressure will increase.

(i) Temperature: As the temperature of the liquid is raised, more molecules get evaporated and thus exert more pressure. So vapour pressure will increase.(ii) Intermolecular forces: If the intermolecular attractions between the molecules of liquid are stronger, then its vapour pressure would be low as it would be difficult to convert that liquid into vapours.

(i) Temperature: As the temperature of the liquid is raised, more molecules get evaporated and thus exert more pressure. So vapour pressure will increase.(ii) Intermolecular forces: If the intermolecular attractions between the molecules of liquid are stronger, then its vapour pressure would be low as it would be difficult to convert that liquid into vapours.(iii) Addition of solute: Addition of solute raises the boiling point of any liquid, i.e. its will boil at a higher temperature. Thus it will lower the vapour pressure of that liquid.

(i) Temperature: As the temperature of the liquid is raised, more molecules get evaporated and thus exert more pressure. So vapour pressure will increase.(ii) Intermolecular forces: If the intermolecular attractions between the molecules of liquid are stronger, then its vapour pressure would be low as it would be difficult to convert that liquid into vapours.(iii) Addition of solute: Addition of solute raises the boiling point of any liquid, i.e. its will boil at a higher temperature. Thus it will lower the vapour pressure of that liquid.Explanation:

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