Question

Two fair coins are tossed simultaneously. Find the probability of getting:

1) no tail
2) same face on each
3) different faces on the coins​

Answer 1

Answer:

Step-by-step explanation:

probability of no tail = probability of two head = (1/2)×(1/2) = 1/4

same face on each coin = either two heads or either two tails = 1/4 + 1/4 = 1/2

different face of coins = 1 - same face on each coin = 1 -1/2 = 1/2

Answer 2

$When two coins are tossed the results are (HH,HT,TH,TT)</p><p></p><p>Total no. of outcomes =4</p><p></p><p></p><p>1) Exactly one head = only two cases are (HT,TH)</p><p></p><p></p><p>=42=21</p><p></p><p></p><p>2) At least one tail = There are three cases (HT,TH,TT)</p><p></p><p></p><p>=43</p><p></p><p></p><p>3) No. tail = only one case (HH) =41</p><p></p><p></p><p>4) Atmost one head =three cases (HT,TH,TT)</p><p></p><p></p><p>=43.</p><p></p><p>$

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