Two fair coins are tossed simultaneously then the probability of getting no head is A/B',then (A + B)²
is equal to:
A. 1 B. 4 C.5 D.25
Please help me
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Answer:
Let A be the event that ‘at lest one head turns up.
since each coin turns up on either a head or a tail.
Hence, the sample space consists of 25=32 outcomes.
Each outcome having a probability of occurrence as 1/32 .
Then Ac is the event that ‘No head turns up’.
Thus Ac consists of only one outcome,
Hence P(Ac)=1/32
⇒P(A)=1−1/32=32-1/32=31/32
Step-by-step explanation:
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