Question

) Two fair dice are rolled. Find the probability that
a) Both the dice show number 6
b) The sum of the numbers obtained is 1 or 10.
c) Sum of numbers obtained is less than 10
d) Sum is divisible by 3.
(Dec-2008)​

Answer 1

Answer:

Step-by-step explanation:

the probability= all the occurrences/sample space

sample space for this is,

S={(1,1),(1,2),(1,3),.....} IN TOTAL 36 different occurrences can take place.

a) for both six, only one case exists that is 6 on one dice and 6 on the other dice, that is (6,6)

hence, P=1/36

b) you can never get a sum of one unless you have a special dice that starts with zero.

now, for having 10 as the sum total case would be , (4,6) (5,5) (6,4)

hence, P=3/36 that is 1/12

c) Total no. of cases in which sum will be less than ten are 30.

hence, P=30/36 that is 5/6

d) no. of cases in which it is divisible by three are 12

hence, P=12/36 that is 1/3.

Answer 2

Step-by-step explanation:

(a) P of dice show number 6 =1

36

(b)P of the sum of no. obtained is 1 to 10=28

36

=04

06

=02

03

(c)P of the sum of no. obtained less than 10=28

36

=02

03

(d)P of sum is divisible by 3 =13

36

=01

02

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