Question

two fair dice are rolled simultaneously. the probability that 2 will come either time​

Answer 1

The outcomes can be:

1,1; 1,2; 1,3; 1,4; 1,5; 1,6

2,1; 2,2; 2,3; 2,4; 2,5; 2,6

3,1; 3,2; 3,3; 3,4; 3,5; 3,6

4,1; 4,2; 4,3; 4,4; 4,5; 4,6

5,1; 5,2; 5,3; 5,4; 5,5; 5,6

6,1; 6,2; 6,3; 6,4; 6,5; 6,6

Out of these 10 have two in them.

Probability (getting 2) = 10/36 = 5/18

Answer 2

Given: Two fair dice are rolled simultaneously.

To find: The probability that 2 will come either time​.

Solution:

• Probability of an event is the chance of its occurrence.
• It is calculated by dividing the total number of favourable outcomes by the total number of possible outcomes.
• A dice has a single 2. So, the number of favourable outcomes is one.
• The total possible outcomes are 6 since there are 6 numbers in a dice.
• But two dices that are rolled simultaneously and the probability for either one of them getting 2 can be calculated as,

        $P(E) = \frac{1}{6} + \frac{1}{6}$

                  $= \frac{2}{6}$

                  $= \frac{1}{3}$

Therefore, the probability that 2 will come either time​ is 1/3.