Question

two fair dice are rolled simultaneously what is the probability that the sum of the number obtained is multiple of 3

Answer 1

Two fair dice are rolled simultaneously what is the probability that the sum of the number obtained is a multiple of 3Total number of outcomes =36
Favourable outcomes are (1,2),(1,5),(2,1),(2,4),(3,3),(3,6),(4,2),(4,5),(5,1),(5,4),(6,3),(6,6)
their number=12
required probability =12/36=1/3
hope it helps.

Answer 2

Answer:

Step-by-step explanation:

The total outcomes are as follows

1+1,1+2,1+3........6+5,6+6

So, total outcomes is...

(6)^2 = 36

Desired outcomes =

1+2 , 1+5 , 2+1 , 2+4 , 3+3 , 3+6 , 4+2, 4+5 , 5+1 , 5+4 , 6+3 , 6+6.

No. Of desired outcomes=12.

So,probablity=12/36=1/3=0.3334.