Question

Two fair dice are thrown. Find the probability of getting a number divisible by 2 and 4.

Answer 1

please find the attachment

Answer 2

Answer:  The required probability is 25%.

Step-by-step explanation:  Given that two fair dice are thrown.

We are to find the probability of getting a number divisible by 2 and 4.

Let S denotes the sample space for he experiment of throwing two fair dice and let A be the event of getting a number divisible by 2 and 4.

Then, we have

$S=\{(1,1),(1,2),()1,3},~~.~~.~~.~~,(6,5), (6,6)\},\\\\A=\{(1,3),(2,2),(2,6),(3,1),(3,5),(4,4),(5,3),(6,2),(6,6)\}.$

That is,

n(S) = 36  and   n(A) = 9.

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{9}{36}=\dfrac{1}{4}=\dfrac{1}{4}\times100\%=25\%.$

Thus, the required probability is 25%.