Question

Two fair dice are thrown. Find the probability that the total score is (i) 10, (ii) at most 6, (iii) multiple of 4. (iv) either a perfect square or less than 5. (v) The sum of the numbers obtained is 7. (iv) the product of the numbers is a prime number​

Answer 1

Answer:

total outcomes=6X6=36

I)fav outcomes

6,4

4,6

5,5

prob= 3/36=1/12

ii) 12/36

=1/3

iii) 2/36= 1/18

iv) 4,4

1,2,3,4

1,2,3,4

10/36 =5/18

v) 1+6

6+1

2+5

5+2

3+4

4+3

5/36

Answer 2

(I) 3/36= 1/12
(II) 15/36= 5/12
(III) 9/36=1/4
(IV) 10/36=5/18
(V) 6/36=1/6
(VI) 6/36=1/6