Question

Two faraday of electricity is passed through a solution
of CuSO4 The mass of copper deposited at the cathode
is (at.mass of Cu=63.5 amu)
(1) Og
(2)63.5g
(3)2g
(4) 127g​

Answer 1

Answer:

63.5 g

Explanation:

Cu2+ + 2e_>Cu

therefore 2 moles of electricity is required to deposit 1 mole of Cu

i.e 2F will deposit 1 mole of Cu

i.e 63.5 g