Two fields have the same perimeter one is a square of side 72meters.And another is a rectangle of length 80metres.Which field has the greater area and by how much
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mate your solution is here,
side of square field=72m
area of square=side*side
=72*72m^2=5184m^2
perimeter of square=4*side=4*72=288m
and it is given that, perimeter of square =perimeter of rectangle=288m
2(l+b) =288m
2(80+b) =288m
80+b=288m/2
b=144m-80m
b=64m
Area of rectangular field=length * breadth
=80m*64m=5120m^2
So the area square field is more than the area of the rectangular field by 5184-5120=64m^2
side of square field=72m
area of square=side*side
=72*72m^2=5184m^2
perimeter of square=4*side=4*72=288m
and it is given that, perimeter of square =perimeter of rectangle=288m
2(l+b) =288m
2(80+b) =288m
80+b=288m/2
b=144m-80m
b=64m
Area of rectangular field=length * breadth
=80m*64m=5120m^2
So the area square field is more than the area of the rectangular field by 5184-5120=64m^2
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