Two films on the roller skate are standing 5 m apart facing each other one of them throws a ball of 5 KG to words are there who catches it how is this activity affect the position of the two explain your answer
Answers
Answer:
Let us say mass of the friends is m kg each. For example...
We apply the conservation of momentum principle here. Let us say the ball of 2 kg is thrown with a velocity u by one friend on the left, towards his friend on the right. We take u as the horizontal component of velocity. Initially the friends were stationary. Let the friend on the left move further left with a velocity v.
m v + 2 kg * u = 0 v = - 2 u / m
Let us say the second friend move further to right with a velocity V after catching the ball.
2 * u + m * 0 = (m+2) * V
V = 2 u / (m+2)
The friends separate with a relative speed =
V - v = 2u / (m+2) + 2 u / m
= 2 u [ 2m + 2 ] / m (m+2)
= 2 u * 2m / m * m = 4 u / m if m >>2 kg
Explanation:
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Answer:
the answer is 19537e1+4(557)