Two finite sets have m and n elements. The total number of subsets of the first set is 112 more than the total number of subsets of the second set. Find the valuesof m and n.
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m=6 and n=3…
As,
no. of subsets which has element m = 2^m
No. Of subsets which has element n = 2^n
So, ATQ
2^m= 2^n +56
2^m - 2^n = 2³.7
(2^n /2^n . 2^m) - 2^n = 2³.7
2^n ( 2^m-n - 1) = 2³.7
Now, on comparing
We get,
2^n = 2³ or
n=3 ……(i)
S.o,
2^m-n -1= 7
2^m-n=8
2^m-n= 2³ or
m-n= 3
m-3= 3. From(i)
m=6
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