Question

Two firecrackers bursted together on same side of a boy. If the boy hears the
sound of firecrackers in between interval of time 0.1 s. Distance between the
crackers is (Speed of sound in air = 330 m/s]​

Answer 1

Given:

Two firecrackers bursted together on same side of a boy. If the boy hears the sound of firecrackers in between interval of time 0.1 s.

To find:

Distance between the crackers is ?

Calculation:

Let the sound from cracker situated near the boy travel for t sec , so the sound from far away cracker will travel for (t + 0.1 sec)

Distance of near cracker from boy:

$\therefore \: d1 = v \times t$

$\implies \:d1 = 330t$

Distance of far away cracker from boy:

$\therefore \: d2 = v \times (t + 0.1)$

$\implies \:d2 = 330(t + 0.1)$

So, distance between the crackers:

$\therefore \: d = d2 - d1$

$\implies \: d = 330 \bigg(t + 0.1 - t \bigg)$

$\implies \: d = 330 \bigg( 0.1\bigg)$

$\implies \: d = 33 \: metres$

So, the crackers are situated 33 metres from one another.