Question

Two fixed, parallel infinite wires of uniform linear charge density +λ and –2λ respectively are separated by distance d as shown in figure. The magnitude of electric field at a point midway between the two will be Find n

Answer 1

Answer:

value of n is 3

3lamda/πd epsilon not

Answer 2

Given:

Two fixed, parallel infinite wires of uniform linear charge density +λ and –2λ respectively are separated by distance d.

To find:

Magnitude of electric field at a mid-point of the system?

Calculation:

Since one wire is having positive linear charge density and the other having negative linear charge density, the net field intensity will be algebraic addition.

$E = E1 + E2$

$\implies \: E = \dfrac{2k \lambda}{ (\frac{d}{2} )} + \dfrac{2k (2\lambda)}{ (\frac{d}{2} )}$

$\implies \: E = \dfrac{4k \lambda}{d} + \dfrac{8k\lambda}{d}$

$\implies \: E = \dfrac{12k \lambda}{d}$

$\implies \: E = \dfrac{12 \lambda}{4\pi \epsilon_{0}d}$

$\implies \: E = \dfrac{3 \lambda}{\pi \epsilon_{0}d}$

So, final answer is:

$\boxed{ \bf \: E = \dfrac{3 \lambda}{\pi \epsilon_{0}d} }$