Two fixed point changes +4q and +2q are separated by a distance a cm in air where should the therd point charge q be placed from +4q to be equilibrium
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- Two fixed charges +4q and +2q
- each seperate by a distance a cm
- put +Q both the charges
- so that charge is in equilibrium
- put +Q charge towards the small +2q charges
- F = kQ1Q1 / R^2
- F1 = 4kqQ / (a - x) ^2
- F2 = 2KqQ / x^2
- F1 = F2
- 4kqQ / ( a - x) ^2 = 2kqQ / x^2
- a - x / x = √2
- a - x = √2x
- a = x (√2 + 1 )
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