Question

Two fixed point charges +4uC and +1uC are separated by 30cm in air. Find the position between them at which the resultant electric field is zero or find the neutral point.

Please answer this its very important

Answer 1

$\mathtt{ \huge{ \fbox{Solution :)}}}$

Given ,

• The two charges 4uC and 1uC are separated by 30 cm in air

Let , P be the point where electric field is zero and " x " cm from first charge and " (30 - x) " cm from second charge

We know that ,

The electric field at point P is zero if

$\large \mathtt{ \fbox{Electric \: field \: due \: to \: q_{1} = Electric \: field \: due \: to \: q_{2} }}$

Thus ,

$\sf \hookrightarrow k \frac{4}{ {(x)}^{2} } = k \frac{1}{ {(30 - x)}^{2} } \\ \\ \sf \hookrightarrow {(30 - x)}^{2} \times 4 = {(x)}^{2}$

Taking square root on both sides , we get

$\sf \hookrightarrow (30 - x) \times 2 = x \\ \\ \sf \hookrightarrow 60 - 2x = x \\ \\ \sf \hookrightarrow 60 = 3x \\ \\ \sf \hookrightarrow x = \frac{60}{3} \\ \\ \sf \hookrightarrow x = 20 \: \: cm$

Hence , the electric field will be zero at 20 cm to the right of first charge

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