Chemistry, asked by sumabolare, 9 months ago

Two flasks A and B have equal volume at 50 Kand 200 K and
have 4 atm and 1 atm pressures,. The flask Acontains H2gas and
Bcontains CH4gas. The collision diameter of CH4is twice that of
H2. Which of the following is true about the mean free path () of
the molecules?​

Answers

Answered by bhardwaj1023
1

Answer:

Formula for mean free path is

λ=

2

πd

2

N

A

P

RT

R=gas constant

T=temperature

N

A

=Avogadro's constant

P=Pressure

d=collision diameter

Let collision diameter of H

2

=d

Then collision diameter of CH

4

=2d

Given:

A⇒H

2

⇒100K→4atm→d

B⇒CH

4

⇒200K→1atm→2d

λ(H

2

)

λ(CH

4

)

=

(

2

×π×(d)

2

×N

A

×4

P×100

)

(

2

×π×(2d)

2

×N

A

×1

P×200

)

ratio=2:1

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