Question

Two flasks of equal volume have been joined by a narrow tube of negligible volume. initially both flasks are at 300K containing 0.6 mol of O2gas at 0.5 atm pressure.One of the flasks is then placed in a thermostat at 600K.calculate number of moles of O2 gas in each flask

Answer 1

Hey buddy,

● Answer- 0.4 mol and 0.2 mol

● Explaination-
Initially, for both flasks,
PV = nRT
0.5 × V = 0.6 × R × 300
V = 360R

Finally,
For flask 1,
P(360R) = xR300
x = 1.2P
For flask 2,
P(360R) = yR600
y = 0.6P


Here, total no moles will remain constant,
n = x + y
0.6 = 1.2P + 0.6P
P = 1/3 atm

So now, no of moles,
x = 1.2×1/3 = 0.4 mol
y = 0.6×1/3 = 0.2 mol

Therefore, the two flasks will contain 0.4 mol and 0.2 mol.

Hope this is helpful...

Answer 2

Answer: 0.4 at 300K and 0.2 at 600K