Two force 5N and 20N acting at an angle of 120 between them,find the resultant force in magnitude and direction?
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Resultant force is calculated by formula:
R = sqrt(A^2 + B^2 + 2ABCosX)
R = sqrt(5^2 + 20^2 + 2*5*20*(-1/2))
R = 18.0 N
Tany = bSinx / (a + bCosx)
= (20*(sqrt(3)/2)) / (5 + 20*(-1/2))
= -3.64
Angle of resultant with 5N is Tan^-1 (-3.64)
R = sqrt(A^2 + B^2 + 2ABCosX)
R = sqrt(5^2 + 20^2 + 2*5*20*(-1/2))
R = 18.0 N
Tany = bSinx / (a + bCosx)
= (20*(sqrt(3)/2)) / (5 + 20*(-1/2))
= -3.64
Angle of resultant with 5N is Tan^-1 (-3.64)
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