Question

Two force each of magnitude 10N acts on a body the forces are inclined at 30 and 60 degree with x axis the x component of their resultant is

Answer 1

Answer:

Take component and add

x component will be 10cos 0

so resultant

$10 \cos(60) + 10 \cos(30)\\ = 10( \frac{1}{2} + \frac{ \sqrt{3} }{2} ) \\= 5( \sqrt{3} + 1) \\\approx \: 13.66 \: \hat i$