two forces 100 N and 300 N are acting at an angle of 60 at same point. Find the magnitude of resultant vector
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The resultant force, R will lie along the longer diagonal of the parallelogram whose sides are the given forces.
Invoking the cosine rule
R2=1002+602–2×100×60cos120∘
From which it is easy to show that R=140N
We have to give the direction of R . Let us find the angle, θ in relation to the force of 60N . We use the sine rule.
sin120∘R=sinθ100
θ=sin−1(100sin120∘)140
θ=38.2∘ to the 60N force.
Explanation:
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tarangagrawal72:
But its answer is tan ^-1 (3√3/5)
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