two forces 100N and 80N act at a point makeing an angle 60° between them. determine the magnitude and direction of resultant
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The resultant force, R will lie along the longer diagonal of the parallelogram whose sides are the given forces.
Invoking the cosine rule
R2=1002+802–2×100×80cos120∘
From which it is easy to show that R=140N
We have to give the direction of R . Let us find the angle, θ in relation to the force of 80N . We use the sine rule.
sin160∘R=sinθ100
θ=sin−1(100sin120∘)140
θ=38.2∘ to the 80N force
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