Two forces
(10i +14j) Nand (6i + 10j) N act
upon a body of mass 8 kg. Then the
acceleration of the body is
A
(2ỉ +3j) ms
B (3j +2i) ms
c (5j +2i) ms
D
(2i+6j) ms
Answers
Answered by
2
Answer:
Force
F
=10
i
^
−3
j
^
+3
k
^
Mass M=100g
Displacement (6
i
^
−5
j
^
−3
k
^
)(10
i
^
−2
j
^
+7
k
^
)
Displacement
d
=4
i
^
−7
j
^
+10
k
^
Work = Force . displacement
=
F
.
d
=(10
i
^
−3
j
^
+6
k
^
)(4
i
^
−7
j
^
+6
k
^
)
=(10×4)+(7×3)+(10×6)=121J
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