Question

Two forces 20N and 10N are acting
an angle 120°. What is the
magnitude resultant of forces? *​

Answer 1

Answer:

Answer :

$\sqrt{ {a}^{2} + {b}^{2} + 2ab \cos( \alpha ) }$

$\sqrt{ {20}^{2} + {10}^{2} + 2 \times 10 \times 20cos(120) }$

$400 +100 + 40 \times \frac{ - 1}{2}$

$\sqrt{500 + 40 \times - \frac{1}{2} }$

$\sqrt{500 - 20}$

$\sqrt{480}$

$2 \sqrt{120}$

is the answer of this question

Answer 2

a

2

+b

2

+2abcos(α)

\sqrt{ {20}^{2} + {10}^{2} + 2 \times 10 \times 20cos(120) }

20

2

+10

2

+2×10×20cos(120)

400 +100 + 40 \times \frac{ - 1}{2}400+100+40×

2

−1

\sqrt{500 + 40 \times - \frac{1}{2} }

500+40×−

2

1

\sqrt{500 - 20}

500−20

\sqrt{480}

480

2 \sqrt{120}2

120

is the answer of this question