Question

Two forces 3N and 1N act at

normal to each other.The resultant

is​

Answer 1

Question:

Two forces 3N and 1N act at normal to each other. The resultant is ?

To find:

★ Resultant force

Answer:

$Resultant\: force\:is\:\underline{\bf{\sf\pink{3.162N}}}$

Given:

★ Two forces are given,

• 3N
• 1N

$\star \: F _{1}=a = 3N$

$\star \: F _{2} =b= 1N$

Step-by-step explanation:

There are two methods,

1. PYTHAGORAS THEOREM
2. COSINE RULE

PYTHAGORAS THEOREM

$\boxed{ {a}^{2} + {b}^{2} = {c}^{2} }$

Let

• a² be 3
• b² be 1
• c² be R²

$\implies \boxed{ {R}^{2} = {a}^{2} + {b}^{2} }$

$\implies {R}^{2} = {(3)}^{2} + {(1)}^{2}$

$\implies {R}^{2} = 9 + 1$

$\implies {R}^{2} = 10$

$\implies R = \sqrt{10}$

$\implies \boxed{R = 3.162N}$

$\therefore Resultant\: force\:is\:\underline{\bf{3.162N}}$

$\underline{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$

⚠️ Note ⚠️

★ The above method is done by Pythagoras Theorem .

★ It is the simplest method than Cosine Rule .

Answer 2

Answer:

Required resultant is 3.1623 N.

Step-by-step explanation:

Given,two forces are 3N and 1N.

It is give that they act at normal to each other.

Here we want to find resultant.

We know,if two forces are a and b act at normal to each other and their resultant is r then,${r}^{2} = {a}^{2} + {b}^{2}$

Here a=3 N and b= 1 N

So,

${r}^{2} = {3}^{2} + {1}^{2} = 9 + 1 = 10$

So,$r = \sqrt{10} = 3.1623$

Required resultant is 3.1623 N.

Extra information,

Resultant force helps us explain whether the forces are balanced there is all forces act in a particular direction.Unit of resultant is always Newton because resultant is also a one types of force.