Question

two forces 3N and 4N are acting on a point O. if an angle between there 2 forces is 90°, find the resultant of there two forces.

Answer 1

HELLO HERE IS YOUR ANSWER .
FORCE 1 =3N
FORCE 2 =4N
ANGLE =90°
FORMULA FOR RESULTANT
R =√A^2+B^2+2AB COS THETA
R =√3^2 +4^2 +0 : COS 90° =0
R=√9+16
R=5N .
HOPE IT HELPS . PLS MARK IT AS BRAINLIEST

Answer 2

Given,

2 forces 3N and 4N are acting on a point O.

The angle between the 2 forces = 90°

To find,

The resultant of these two forces.

Solution,

We can simply solve this numerical problem by using the following process:

Mathematically,

If 2 forces of magnitude X and Y are acting on a point and the angle between them is A°, then,

The resultant force

= √(X^2 + Y^2 + 2XY.Cos A°)

Now, according to the question;

The resultant of these two given forces

= √{(3N)^2 + (4N)^2 + 2(3N)(4N). Cos 90°}

{according to statement-1}

= √{9 N^2 + 16 N^2 + 2(3N)(4N)×0}

{Since Cos 90° = 0}

= √(25 N^2)

= 5 N

Hence, the resultant of these two given forces is equal to 5N.