Question

Two forces 5 kgwt and 10 kgwt acting with an inclination of 120 between them.What is the angle which the resulutant makes with 10 kgwt? ​

Answer 1

Answer:

30°

Explanation:

Let P be the force of 5 kg weight and Q be the force of 10 kg weight.

By parallelogram law of vector addition, the resultant is,

R^2=P^2+Q^2+2Pcostheta

R^2=25+100+100cos120

R=5√3 weight

Let α be the angle made by R with 10 kg weight.

tanα=psin theta /P+Q cos theta

tanα=

5+10cos120

5sin120

tan a =1/√3

α=30 °

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