Question

two forces 50N and 60N are inclined at an angle of 60° find the resultant force​

Answer 1

Answer:

The final answer is 95.39

Explanation:

Given,

We have two forces 50N and 60N which is inclined at an angle of 60. We need to find the value of the resultant force. First we need to find the magnitude of the force.

We have the equation of the resultant force

R = $\sqrt{p^2+q^2 + 2pqcos\theta}$

Where

p is the first force and q is the second force and $\theta$ is the angle between the forces.

Substituting the values,

p = 50

q = 60

$\theta$ = 60

R = $\sqrt{50^2 + 60^2+2*60*50*cos60}$

R = $\sqrt{2500+3600+2*3000/2}$

R = $\sqrt{6100+3000}$

R = $\sqrt{9100}$

R = 95.39

Hence the resultant force is 95.39.

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