Question

Two forces 5N and 10N are inclined to each other at an angle of 120 degree. What is the angle which the resultant makes with 10N force?

Answer 1

Angle is 30 degree with the 10 N force

Explanation:

just draw 5N and 10 N force at an angle of 120 ° then resolve 5N force and just find the angle. .

Hope so it clarifies your doubts

Answer 2

Answer is 30°.

Parallelogram law of Vector : The parallelogram law of force is that when two vectors acting on a particle at the same time are represented  by  two adjacent sides of a parallelogram drawn from a point, the size and direction are represented by a diagonal. The resulting vector is a parallelogram drawn from the same point.

Given  : Two forces 5N and 10 N. And angle between them is 120°

To Find : Angle of resultant with 10N force.

Solution : here Q = 5N and P = 10N force.

Direction of resultant -

tan(θ) = $\frac{Qsinx}{P + Q cosx}$

tan (θ) = $\frac{5 \times sin120}{10 - 5 cos120}$

tan (θ) = $\frac{5\times\sqrt{3/2} }{\frac{15}{2} }$

tan (θ) = $\frac{1}{\sqrt{3} }$

θ = tan⁻¹ $(\frac{1}{\sqrt{3} } )$

θ = 30° .with 10 N force.

Hence, resultant will make 30° angle with 10N force.

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