Question

Two forces act on a particle simultaneously as shown in the figure. Find net force in milli newton on the particle. [Dyne is the CGS unit of force].
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Answer 1

Answer:

Answer:

Dimensional formula of Force F [M1 L1 T-2]

So a =1, b=1, c=-2

Now because Newton is in m.k.s system,We Have.

M1 = 1kg, L1 = 1m, T1 = 1s

M2 = 1g, L2 = 1cm, T2 = 1s

n1= 1 Newton

n2 = ?

Using the formula

n2= n1[M1/M2]a [L1/L2]b [T1/T2]c

n2= 1 [1kg/1g]1 [1m/1cm]1 [1s/1s]-2

n2= 1[1000g/1g]1 [100cm/1cm]1 x1

n2= 1000×100 = 100000

= 105 dynes

Explanation:

Answer 2

Answer:

100 dyne = 1 mili newton

Net Force = √a²+b²+2ab

 =√(1)²+(1)²+2×½

 =√1+1+1

 =√3 = 1.732 ≈ 1

Explanation: