Question

two forces are acting on a body (in straight line) with magnitudes 10n and 8n in the same direction calculate the net force acting on the body
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Answer 1

Answer:

18 N

Explanation:

Since both the forces are acting in the same line, we can add them directly.

Total force acting = 10N + 8N

                              = 18N

                Method 2:

Using vector law of addition:

R = √A² + B² + 2ABcosθ

   = √10² + 8² + 2(10)(8)cos0°

   = √100 + 64 + 160(1)

   = √324

   = 18

Resultant is 18 N

Answer 2

Answer:

Given :-

Two force of 10 N and 8 N

To Find :-

Net force

Solution :-

This can be done by 2 method.

• Method : 1

Since, they are in straight line so,

$\bf \red{ Net \: force = A + B}$

Net force = 10 + 8

Net force = 18 N

• Method : 2

We know the vector formula

$\bf \blue{ \sqrt{ {a}^{2} + b {}^{2} + 2ab \cos( \theta) } }$

Where

cos ∅ = 0⁰

Since they are in straight line,

So angle is 0

$\sf \: \sqrt{ {10}^{2} + 8 {}^{2} + 2(10)(8) }$

$\sf \: \sqrt{100 + 64 + 160(1)}$

$\sf \: \sqrt{260 + 64}$

$\sqrt{324}$

$\sf \: 18 newton$