Question

Two forces are such that the sum of their magnitudes is 18 N and their resultant is perpendicular to the smaller force. Then the magnitudes of the forces are​

Answer 1

Answer:

Correct option is

B

13N,5N

Let the  smaller force be B ,the larger force be A, resultant being C.

Given: ∣A∣+∣B∣=18,∣C∣=12

A,B,C simply form a right angled triangle with base B vector,hypotenuse being A.

So, you have one equation with you: A+B=18

A2=B2+C2A2−C2=B2(A+B)(A−B)=144(A−B)18=144A−B=18144=8

So simply solving both equations: A-B=8 and A+B=18

Adding both:

2A=26

A=13

B=5

Explanation:

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