two forces are such that the sum of themagnitude is 18N and there resultant has magnitude 12N and is perpendicular to the smallest force then the magnitudes of forces are
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12*18 is the answer
tell in what method we should solve or the question may be incomplete
tell in what method we should solve or the question may be incomplete
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A + B = 18
12= √(A2 + B2 + 2AB cosθ)
tan α= (B sin θ)/(A + Bcosθ)
on substituting α = 90, cos θ = -A/B
Solving, A = 5 N and B = 13 N