Question

two forces each of 20 n acts on a body at 120 degree then the magnitude and direction of resultant is​

Answer 1

Answer:

The forces are equal then resultant will be same to forces.. as given,

R^2=(20)^2+(20)^2+2.20.20.COS 120

or,R^2=400+400— 800×1/2

or,R^2=800— 400

or,R=(400)^1/2

therefore…R=20 N ans…

Now..We know..

tan120=(20+20SIN A)÷(20+20COSA)

or,—(3)^1/2=(1+SINA)÷(1+COSA)

or,—(3)^1/2—(3)^1/2COSA=1+SINA

or,SINA/COSA=(—(3)^1/2)÷2.73

or,tanA=— 0.63

or,A=tan^-1(-0.63)

`´,A= 147.80° OR -32.2° ans….

Answer 2

Answer:

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