Question

Two forces each of 5 N act vertically upwards and
downwards respectively on the two ends of a uniform
metre rule which is placed at its mid-point as shown in
the diagram. Determine the magnitude of the resultant
moment of these forces about the mid-point.
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Answer 1

Answer:

It's correct answer

Explanation:

Given: F1=F2=5N,d1=d2=0.5m

Torque τ=F×d

tau1=F1×d1=5N×0.5 m

=2.5 Nm (Anti-clockwise)

τ2=F2×d2=5N×0.5 m

=2.5 Nm (Anti-clockwise)

The resultant moment of force =τ1+τ2

=2.5+2.5=5 Nm in Anti clockwise direction

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