Question

Two forces each of
magnitude 10 N act
vertically upwards
and downwards
respectively at the
two ends A and B
of a uniform rod of length 4m which is pivoted at its mid point o . determine the magnitude of the resultant moment of forces about the pivot o.​

Answer 1

Explanation:

Magnitude of force applied on each end =10N

The moment of force τ=r×f.

Hence in bothe the cases, moment of force is in the clockwise direction, and the moment of forces add to one another.

The magnitude of τ =2×10×2=40 Nm in the clockwise direction.

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