Question

two forces each of magnitude 10 Newton Act at a point at an angle of 120 degree with each other. what is the magnitude of resultant force?​

Answer 1

Two forces each of magnitude 10N act simultaneously on a body with their directions inclined to each other at an angle of 120∘and displaces the body over 10m along the bisector of the angle between the two forces. Then the work done by force is. Solution : W=FS=cos

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Answer 2

Given :-

◉ Two forces A and B of magnitude 10 newton act at a point at an angle of 120° with each other.

To Find :-

◉ Magnitude of resultant vector.

Solution :-

We know for any two given vectors of magnitude A and B at an angle of, say θ , the magnitude of the resultant is given by:

⇒ R = √(A² + B² + 2ABcosθ)

To Be Noted :-

The angle between the vectors must be measure either by joining the vectors tail-to-tail or head-to-head.

Here, Since the force is acting at a same point and the given angle is 120° . So the angle between the vectors is 120° (head-to-head)

So, We have

⇒ |R| = √(10² + 10² + 2×10×10×-1/2)

⇒ |R| = √(100 + 100 - 100)

⇒ |R| = √100

⇒ |R| = 10 newton

Hence, The resultant vector would also have the magnitude of 10 newton.

Some Information :-

☛ The subtraction of two vectors A and B is given by:

⇒ R = A + (-B)

⇒ R = √(A² + B² - 2ABcosθ)

Where,

• θ is the angle after shifting the vector.