Two forces each of magnitude 10N acting on a body, if the forces are inclined at 30° and 60° with x axis, the X component of the resultant is? A)10N B)136.6N C)1.366N D)13.66N
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Answer:
13.6N
Explanation:
X component of a vector = cosine of the vector
X component of force = Fcos30⁰ + Fcos60⁰ (Since two forces are acting on it)
= 10 ( √3 + 1) ÷ 2
5 ( 1.72 + 1)
5 × 2.72
= 13.6N
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