Two forces each of magnitude 2N act vertically upwards and downwards respectively at the two ends of a uniform rod of length 1m which is pivoted at its centre. determine the resultant moment of forces about the mid point of the rod
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Answer:
Resultant moment = 2 N m
Explanation:
Figure shows a rod AB of length 1 m is pivoted at centre C. At A, 2N force acting upward and at B 2N force acing downward.
If we take moment of the forces about C, both moments are clockwise moments.
Moment at A = 2N × 0.5 m = 1 N m
Moment at B = 2N × 0.5 m = 1 N m
Resultant moment = 2 N m
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